x^2+5.6x+7.2=0

Solution for x^2+5.6x+7.2=0 equation:

x^2+5.6x+7.2=0

a = 1; b = 5.6; c = +7.2;
Δ = b2-4ac
Δ = 5.62-4·1·7.2
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{2.56}}{2*1}=\frac{-5.6-\sqrt{2.56}}{2}
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$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{2.56}}{2*1}=\frac{-5.6+\sqrt{2.56}}{2}
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